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> for ( my $x =0 ; $x < @ARGV ; $x++ ) {
>
> $#ARGV is the last element number of the array
> @ARGV, @ARGV is the count of elements.
As a Perl hack I'd offer this as a much clearer form of the for() loop:
for ( my $x =0 ; $x < scalar(@ARGV) ; $x++ ) {}
Your version works because the return value of a list in scalar context
is the number of elements but unless you are a heavy Perl user that is
pretty obscure and one reason a lot of people say Perl is unreadable.
The scalar() call makes that explicit and I think it's easier to grok.
Having said that, the more often seen and understood way to loop over
each element in a list is:
foreach my $x (@ARGV) {}
http://www.perl.com/pub/a/2000/04/raceinfo.html
http://www.perl.com/pub/a/2000/06/commify.html
Glad it's working for you in any case,
Aric
Aric Czarnowski
Unimax Systems Corporation
612-204-3634